How to use fmincon for my function with 2 variables?

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Sanjal C C
Sanjal C C 2018-6-23
编辑： Walter Roberson 2018-6-24
function [pointoftangency] = Tangentpoint(X,Y,amplitude)
ptf=amplitude*sin(2*pi*x./25)+((2*pi*amplitude/25)*cos(2*pi*x./25)*(X-x))-Y
end
and my constraint equation is
amplitude*sin(2*pi*x/25)=0;
How do I solve this using fmincon??
  2 个评论
Rik
Rik 2018-6-24
Have a read here and here. It will greatly improve your chances of getting an answer.
You can 'trick' fmincon by entering your variables as a vector into your function.
Walter Roberson
Walter Roberson 2018-6-24
Which are the two variables? You have X, Y, and amplitude as inputs to Tangentpoint, and your code also uses x as well. Your code computs ptf, but your function expects pointoftangency to be output.
What is it that needs to be minimized?

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回答（1 个）

Walter Roberson
Walter Roberson 2018-6-24
编辑：Walter Roberson 2018-6-24
Assuming that it is ptf that needs to be minimized with X, Y, amplitude constants, then the solution is that ptf becomes arbitrarily small (towards negative infinity) as x approaches positive infinity, assuming the value 2*Pi*amplitude*(X-50*Z)*(1/25)-Y when x = 50*Z with Z being an integer.
ptf becomes arbitrarily small (towards negative infinity) as x approaches negative infinity when x = 50*Z+25 with Z being an integer.

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