清空筛选条件
清空筛选条件

How to symbolically differentiate a function with respect to a different function

7 次查看（过去 30 天）
Peter
Peter 2012-6-11
编辑： Walter Roberson 2018-1-18
Let's say I have the following defined as symbolic functions:
phi(t),
phi_dot(t),
alpha(t),
alpha_dot(t),
and I have the equation
x = phi_dot*cos(alpha)
I want to take the derivative of x with respect to phi_dot;
y = diff(x, phi_dot)
but I cannot do so without getting the error that follows:
Error using mupadmex
Error in MuPAD command: Invalid variable. [stdlib::diff]
Error in sym/diff (line 44)
R = mupadmex('symobj::diff', S.s, x.s, int2str(n));
I can easily differentiate with respect to time, for example. However, I need the partial derivative of the function with respect to, for example, phi_dot. The output I expect from the above example would be:
y = cos(alpha)
Can anyone help me?

请先登录，再回答此问题。

采纳的回答

Alexander
Alexander 2012-6-12
It seems as if you cannot differentiate with respect to a symbolic function. Maybe it helps if you substitute phi_dot with a normal sym?
>> syms zz; y = diff(subs(x, phi_dot, zz), zz)
y(t) =
cos(alpha(t))
  3 个评论
显示 1更早的评论
Peter
Peter 2012-6-12
Thanks, Alex. I used the concept you suggested, using the subs() command to switch out the variables for functions of time, and I was thus able to take the time derivative of the equations.

请先登录，再进行评论。

更多回答（2 个）

dmitry luchinskii
dmitry luchinskii 2018-1-18
编辑：Walter Roberson 2018-1-18
why would you try Functional Derivative of Vector of Functionals https://www.mathworks.com/help/symbolic/functionalderivative.html
Walter Roberson
Walter Roberson 2012-6-12
If phi_dot is not independent of cos(alpha) then diff(phi_dot * cos(alpha)) with respect to cos(alpha) is not going to be cos(alpha)
  3 个评论
显示 1更早的评论
Walter Roberson
Walter Roberson 2012-6-12
Let phi_dot(t) = cos(alpha(t)) . Now differentiate phi_dot(t) * cos(alpha(t)) with respect to phi_dot(t) . You are differentiating phi_dot(t)^2 with respect to phi_dot(t) so the answer must be 2 * phi_dot(t) which would be 2 * cos(alpha(t)), which is *not* the same as cos(alpha(t))
You can only differentiate phi_dot(t) * cos(alpha(t)) with respect to phi_dot(t) and get cos(alpha(t)) if you know that phi_dot(t) is independent of cos(alpha(t)) -- and you have not given us any reason to expect that the two are independent.
You are failing to apply the product rule, http://en.wikipedia.org/wiki/Product_rule
Unlike the situation where variables are assumed to be independent, functions are not assumed to be independent in calculus.
Alexander
Alexander 2012-6-13
That sounds reasonable. That might be the reason why MuPAD refuses to differentiate w.r.t. phi_dot. I just assumed they are independent because that yielded the requested result.
You are right, Peter should double check that this is what he wants.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Common Operations 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by