how swap the bits at position L&P of A(I,j).?

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Sultan Mehmood
Sultan Mehmood 2018-7-11
评论： Guillaume 2018-7-20
A= imread('camera man.png');
k=1;
for I=1:256;
j=1:256;
end
x=0.3;
p=0.343;
for n=2:65536;
if x(n-1)>=0 & x(n-1)<=p
x(n)=x(n-1)/p;
else
x(n)=(1-x(n-1))/(1-p);
end
end
S=(x*255)+1;
Q=0.2;
p=0.343;
for n=2:65536;
if Q(n-1)>=0 & Q(n-1)<=p
Q(n)=Q(n-1)/p;
else
Q(n)=(1-Q(n-1))/(1-p);
end
end
D=(Q*255)+1;
L= mod(S(k),8)+1;
P=mod(D(k),8)+1;
swap??

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采纳的回答

Guillaume
Guillaume 2018-7-11
编辑：Guillaume 2018-7-18
bits = bitget(A(i, j), [L, P]);
A(i, j) = bitset(A(i, j), P, bits(1));
A(i, j) = bitset(A(i, j), L, bits(2));
As an aside, I would strongly recommend that you declare x and Q as:
x = [0.3, zeros(1, 65535)];
Q = [0.2, zeros(1, 65535)];
to avoid the constant reallocations that your code is doing.
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Sultan Mehmood
Sultan Mehmood 2018-7-20
what is mean by "bits(1),bits(2)"? because code is running only for first entry.
Guillaume
Guillaume 2018-7-20
bits(1) is the bit that bitget extracted at position L, bits(2) is the bit that bitget extracted at position P.
documentation for bitget
documentation for bitset

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