regexp split at first whitespace

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Vincent Scalfani
Vincent Scalfani 2018-7-14
评论： Simon 2023-4-25
I have a cell dataset like this, where it is a string of letters and numbers all in one column (many rows):
data =
'0R 2 2 0'
'1R 2 0 0 4'
'2R 2 2 0 1 1 1'
'3R 2 2 2 1 1'
I would like to split each row into 2 columns at the first space:
data =
'0R' '2 2 0'
'1R' '2 0 0 4'
'2R' '2 2 0 1 1 1'
'3R' '2 2 2 1 1'
I tried:
splitcells = regexp(data, '\s+','split');
but that splits at each space, creating numerous columns, not 2. How do I get the regular expression to split only at the first space? Thanks

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采纳的回答

Paolo
Paolo 2018-7-14
You may use the once option to split only once at the first occurrence of whitespace.
splitcells = regexp(data,'\s','split','once')
  2 个评论
Vincent Scalfani
Vincent Scalfani 2018-7-14
Thanks so much! If anyone else has this question, you can use the following to unnest the 1x2 cells from the split:
data = vertcat(data{:});
Simon
Simon 2023-4-25
I have the same problem. Thanks for the answers!

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