Generation of a column with constants values that increases for different RANGE of row

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Emerson De Souza
Emerson De Souza 2011-3-28
I'm trying to generate ONE column of numbers in Matlab as follows:
1) let the value be equal 10 for row 1 to 30,
2) let the value be equal 10 + increment (for example increment=8) for row 31 to 60,
3) let the value increase in increments of 8 for each new sequence of row 1 to 30
until final constant value equals a number, (for example, 82)
I tried a loop like this:
for f =1:30
for g=(10:8:82);
h(f,1) = g;
end;end;
but did not work.
My result is only a column with the constant 82
from row 1 until 30.
I wonder if someone could help me.
Thanks
Emerson

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采纳的回答

Oleg Komarov
Oleg Komarov 2011-3-28
1) A( 1:30,1) = 10;
2) A(31:60,1) = 18:8:10+8*30;
3) not clear
  2 个评论
Emerson De Souza
Emerson De Souza 2011-3-28
Dear Oleg
thanks for your answer.
Basically, I want to generate a matrix M of TWO columns and J rows.
An initial value (=XSTART) is fixed for the first column
while the second column runs from a value
YSTART in increments K until a final value YEND .
Then an increment L is added to XSTART
and the second column runs again from
YSTART in increments K until a final value YEND.
The increment L stops if the value of X equals XEND.
For example, let
X runs in increment of 4 from 0 until 12 (XSTART=0, L=4, XEND=8)
The vector components are (0, 4, 8)
Y runs in increment of 5 from 0 until 15 (YSTART=0, K=5, YEND=15)
The vector components are (0, 5, 10, 15)
The resulting matrix should be
0 0
0 5
0 10
0 15
4 0
4 5
4 10
4 15
8 0
8 5
8 10
8 15
I hope this text clarify your doubts
and help you to find the proper sintax two
write a command that generate this matrix for given
set of initial and end values for x and y and their respective increments.
Thank you a lot
Emerson

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