Cell array strings storage
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Two questions regarding cell arrays and strings:
1. When I enter a cell array that contains strings through the workspace, sometimes the strings appear in the cells as 'string' (with an apostrophe) and other times the strings appear as they are, without the apostrophe. I couldn't find a rule what happens when, or what is the differenece between these cases.
Is there an explanation for this?
2. When I initialize an array of strings in such a way that the strings appear in the workspace cell array with an apostrophe, and then try to access an element using array{1}, I get:
ans =
cell
'a'
to prevent the "cell" from appearing, I need to double access it (as if it is a cell inside a cell):
array{1}{1}
How can I initialize this in such a way that I can access that string directly without the double {}{}?
Thanks
3 个评论
There should be no reason to have a cell array of string, since a string (array) is the modern replacement of a cell array of char arrays.
Can you give an example of two cell arrays that display differently?
Adam
2018-7-25
You would need to show the code you are using to produce this. Cell arrays contain exactly what you tell them to, no more nor less, so it is down to how you define the code that will determine whether you get cells inside cells or chars. I'm not sure what you mean by strings appearing 'as they are' though. From your context I assume you use string to refer to a char array rather than an actual Matlab string, but chars in a cell array will naturally have the quotes e.g.
>> A = { 'a' }
A =
1×1 cell array
{'a'}
>> A{1}
ans =
'a'
Guillaume
2018-7-25
Yes you are right, every occurrence of the word "string" in my original post was supposed to be "char array".
Anyway, here is some code:
array = {'a', 'b', 'c'};
here, array{1} == 'a'
but then in this case: array2 = cellfun(@(x) regexp(x, '.*', 'match'), array)
you have to do array2{1}{1} to get that same 'a'
采纳的回答
Guillaume
2018-7-25
you have to do array2{1}{1} to get that same 'a'
Yes, of course, because in the second case, you have a cell array of cell arrays of char array, not a cell array of char arrays. You get a cell array of cell arrayw because regexp can return multiple match for each cell of your orignal array. If you want to limit it to just one match (the first one if there are more than one possible), then tell regexp.
Note that your cellfun was completely unnecessary. regexp works directly with cell arrays, so instead of:
array = regexp(array, '.*', 'match'); %cellfun unnecessary
use
array = regexp(array, '.*', 'match', 'once'); %force only one output from regexp,
5 个评论
Micha
2018-7-25
Normally, if you use the 'tokens' option, it's because you want to divide the match into seperate outputs. Therefore, regexp will store these separate outputs in a cell array. If you just wanted one output, you'd use the 'match' option. You will always get a cell array with 'tokens'.
Note that if you don't use the 'once' option with 'tokens' then the problem (if you can call it that) is worse. If you pass a cell array of char arrays to regexp and ask for 'tokens' without the 'once' you'll get a cell array (for each element of the input cell array) of cell arrays (for each match in a char array) of cell arrays (for each token). With 'once' which still mean just one match, the middle cell array is skipped.
To use your example:
array = {'an apple', 'a pear', 'a grenade'};
array2 = regexp(array, 'a(.)(.)', 'tokens');
array2 is a 1x3 cell array since there are 3 elements in the input cell array. array2{1} is a 1x2 cell array as there are two matches, 'an ' and 'app', whereas array2{2} is a 1x1 cell array as there is only one match, 'a p'. array2{1}{1} contains all the tokens of the first match and is thus a 1x2 cell array since 2 tokens were requested. array2{1}{1}{1} is the 1st token of the 1st match in the first input.
Micha
2018-7-25
Guillaume
2018-7-25
A match can contain any number of tokens (what everybody else calls capturing group). With some regex engines the number of captures returned may vary per match (if the capture is optional and didn't match anything, it may be excluded). In matlab, an optional capture is still returned (as empty) so the count is fixed per match. Since the number of captures can vary matlab wraps them into a cell array, even if your particular regular expression only has one capture. There is no way around that.
However, if you have only one capture, you can usually rewrite the regex into a match by using look-ahead and look-behind.
Or, if you use the 'once' option to force only one match per input, you could just vertcat the outer cell arrays:
array = {'an apple', 'a pear', 'a grenade'};
array2 = regexp(array, 'a(.)([^aeiou ]*)', 'tokens', 'once'); %a 1x3 cell array of 1x2 cell arrays
array2 = vertcat(array2{:}) % a 3x2 cell array, only works if 'once' was specified.
Micha
2018-7-25
更多回答（1 个）
With older MATLAB versions the rule was very simple: all arrays were displayed without the outermost array brackets/parentheses (and only showing the contents for the first nesting and only scalar numeric inside cells):
Char array:
>> 'abc' % -> remove ''
ans =
abc
>> {'abc'} % -> remove {}
ans =
'abc'
>> {{'abc'}} % -> remove {}
ans =
{1x1 cell}
Scalar numeric:
>> 1 % -> remove [] (implicit)
ans =
1
>> {1} % -> remove {}
ans =
[1]
>> {{1}} % -> remove {}
ans =
{1x1 cell}
Numeric array:
>> 1:3
ans =
1 2 3
>> {1:3}
ans =
[1x3 double]
>> {{1:3}}
ans =
{1x1 cell}
At some point recently this seems to have changed for cell arrays...
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