Intersection between line and function
显示 更早的评论
hello i draw graphics on matlab based on data found in tables, and what i'm trying to do is project a Y value and find its equivalent X, i give you the code used to create the projection Y, as well as the graph
xlim([0,50])
YV = [min(X1)-0.1:0.01:max(X1)+0.1];
XVmax = zeros(1,numel(YV));
j = [1:numel(YV)];
XVmax(j)= max(Y2_max);
plot(YV,XVmax,'--m')
回答（1 个）
%%Some data
x=0:.9:20;
y=x.^2
%%Set threshold
t=200;
yt=[t t]
xt=[min(x),max(x)];
P=InterX([xt;yt],[x;y])
h=plot(x,y,'+-k',...
xt,yt,'r',...
P(1),P(2),'bo')
set(h(3),'markerfacecolor',[1 0 0])
Note that the resolution of the x-range is quite poor, yet the intercep is accurate.
类别
在 帮助中心 和 File Exchange 中查找有关 Graphics Performance 的更多信息
2018-8-3
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
