cellstr(char(alarm_no(:).')) is not working properly; for same number it is showing empty and for same it was showing exact value.

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Ahsen Noor Subhopoto 2018-8-6

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https://ww2.mathworks.cn/matlabcentral/answers/413776-cellstr-char-alarm_no-is-not-working-properly-for-same-number-it-is-showing-empty-and-for-sa

评论： Ahsen Noor Subhopoto 2018-9-22

Hi. I have two data sets; one is keys (A)and another one is variables to each keys (B) Here B is alarm_no whose length is 36*1. The reason I am using cellstr(char(x)) because for each A(keys) there are many values in B. In short I want data = [A(1) B(:,1)].

since dimensions are not matching; A is 1x1 now and B is let's say Px1. I am using cellstr which makes it 1x1 cell.

raw_data = cellstr(char(alarm_type(:).')); %alarm_type is B here and I am making it 1x1 cell to get desired
retrieved_data = double(cell2mat(raw_data));     %to check if original data is extracted or not

but unfortunately, I can't last element is empty. last element of original data is 9 which is also repeated in many other places but I am getting 9 back from those rows but not the last one.

original_data1 = [2 9 3 9 9 9 2 1 4 9 2 0 2 3 4 2 3 2 3 0 2 9 3 1 1 0 1 1 0 2 3 4 4 4 4 9]

retrieved_data = [2 9 3 9 9 9 2 1 4 9 2 0 2 3 4 2 3 2 3 0 2 9 3 1 1 0 1 1 0 2 3 4 4 4 4]

size(original_data1)= 36x1
size(retrieved_data)= 35x1
raw_data
'                '

If anyone of you know why this is happening and how to solve this?

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Adam Danz 2018-8-6

Please provide a minimal working example of the error you're getting. This should include a sample of your data that causes the problem, the code the causes the problem, and a clear description of what the problem is.

Ahsen Noor Subhopoto 2018-8-6

在 MATLAB Online 中打开

I have posted a picture which shows the data A B C D columns. A is unique let's say 35219, where as B C D are details related to A.

I am creating a data. in next iteration A is changed let's say 35242 and has different length. I want to store those A and related B C D of A after previous A has reached to end.

In short, as seen from the image I want to store 35242 (A) and its related details to be stored on data(36,:)

By replacing cellstr(char(C(:).')) with

D = cellstr(num2str(C)) %data is provided in the image (4th column). and D is just dummy variable

has solved the problem. But still i didn't get why cellstr(char(9)) is giving empty matrix in the raw_data(end) which causes 9 not to be retrieved in the retrieved_data(end).

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