Changing the size of Vector (n no. of zeros to one zero and n no. of ones to 1)

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ARN
ARN 2018-8-21
评论： ARN 2018-9-12
Hi all, I have a vector A and i need to convert it into B. How can i do that with coding? The last value is the only exception in terms of size;
zer= zeros(1,20);
on= ones(1,20);
A=[zer zer on on zer on zer on zeros(1,10)];
B=[0 0 1 1 0 1 0 1 0];
If found zeros put one zero in vector B and if ones then 1 in vector B

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Rik
Rik 2018-8-21
编辑：Rik 2018-8-21
This code should work to remove duplicate values.
A=[1 1 0 0 1 1 1 0 1 0 1];
%A=randi([0 1],1,100);
d=[false diff(A)==0];
A(d)=[];
old code:
If your input follows this pattern strictly, you can just use indexing to get the values:
zer= zeros(1,20);
on= ones(1,20);
A=[zer zer on on zer on zer on zeros(1,10)];
B=[0 0 1 1 0 1 0 1 0];
B2=A(1:20:end);
isequal(B,B2)
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Rik
Rik 2018-8-21
Then B2=A(1:20:end); will work. It selects the first from every 20 elements in your vector, so it condenses your 1120 element vector down to 56 elements. Then call to end in that indexing takes care of any larger vector.
ARN
ARN 2018-9-12
Hi, Hope u can help again
A1= [- - - - - - - - - 15:30:00 15:30:01 15:30:02 15:30:03 15:30:04 15:30:05 15:30:06 15:30:07 - - - - 15:30:12 15:30:13 15:30:14 15:30:15 15:30:16 15:30:17 - - - - - - 15:30:24 15:30:25 15:30:26 15:30:27 - - 15:30:30 15:30:31 - - ];
How can i get B1 from A1 . A1 is random will change everytime
B1= [0 15:30:00 15:30:07 0 15:30:12 15:30:17 0 15:30:24 15:30:27 0 15:30:30 15:30:31 0];
Thanks, Link to the question: https://www.mathworks.com/matlabcentral/answers/418675-getting-the-indices-of-an-array-with-conditions

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