double array of 0's and 1's conversion help
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I have an array of 0's and 1's
Im trying to convert the 0's to nans and 1's to another value.
A(find(A==1)=256; %this part works
A(find(A==0)=NaN; %this part doesn't
when i try to replace the 0's, it replaces everything in the array with NaN, even though find(A==0) does return only the indices of where that array has a 0 value.
is there technical thing I'm missing here?
回答（2 个）
Walter Roberson
2012-6-20
A(A==1) = 256;
A(A==0) = NaN;
If you want to live a life of confusion, and you only have 0 and 1s in the matrix,
A = A ./ A * 256;
4 个评论
the cyclist
2012-6-20
Walter, I recognize that your syntax avoids the unnecessary find(), but what's the use case in which your syntax works, but David's doesn't? I'm puzzled.
Tom
2012-6-20
He may have left the bracket off like in the question?
Walter Roberson
2012-6-20
Reduces the steps that can go wrong ?
David C
2012-6-20
David C
2012-6-20
2 个评论
Sean de Wolski
2012-6-20
What happens if you run this:
A = double(rand(10)>0.5);
A(A==1) = 256;
A(A==0) = NaN;
A
Walter Roberson
2012-6-20
Try breaking it down and do some experiments to see which step is going wrong:
A
T = A == 0
B = A;
A(T) = NaN
B(1) = NaN
C = rand(size(A));
C(T) = NaN
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