0x1 matrix getting while using find function
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Am getting 0x1 matrix while using find function to retreiv the indices,i have tried to use the max function in the array and then used find function still getting 0x1 empty double matrix error.Could you please help as when am using the same function to retriev the other indices am getting proper results
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Stephen23
2018-9-10
编辑:Stephen23
2018-9-10
You are doing an exact comparison of floating point numbers, which is not recommend because of the exact problem that you are having. Always compare the difference of floating point numbers against a tolerance:
abs(A-B)<=tol
The values that you are trying to compare cannot be exactly represented using binary floating point numbers, and are not the same. What you see printed in the command window is the closest representation to 5 or 16 significant digits, depending on your current format setting. To see the "real" value download James Tursa's FEX submission:
Use James Tursa's num2strexact and you will see that none of those values really have the exact value 2.11. All you are looking at is a representation of those floating point numbers displayed in the command window, to the precision defined by your format setting. Just because you see 2.11 displayed tells you nothing about the "real" floating point number's value.
You need to learn about the limits of floating point numbers. Start by reading these:
This is worth reading as well:
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the cyclist
2018-9-10
My best guess here, with the limited information you have given, is that you are trying to compare a number to one that is not exactly equal, due to floating point representation.
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Guillaume
2018-9-10
Clearly, you've not read properly the answers (also look at Stephen's comment) or not doing the comparison properly. You need to understand that you cannot use == to compare floating point numbers. It's easy to demonstrate that it does not work:
a = 2.09 + 0.01 + 0.01 %display 2.11 but is not actually 2.11 due to floating point precision
a == 2.11 %return false
a - 2.11 %display about -4.4e-16
tolerance = 1e-6 %appropriate tolerance for the magnitude of numbers being compared
abs(a - 2.11) < tolerance %proper way to compare floating point number
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