converting a 1x4096 cell, containing binary to 1x(4*4096) double containing binary codes

1 次查看（过去 30 天）
Arsalan
Arsalan 2012-6-23
Hi,
My code generates a x by y matrix, containing random numbers within range of (0 to Order-1) as follow:
x=600; y=8; order=16; bits=randint(x, y ,order,1);
I convert the each integer value to binary as follow
binary=dec2bin(bits,log2(order));
which result in a matrix of class char. I then convert it into a cell array as follow
binary=cellstr(binary); binary=binary';
which results in a long cell row of lenght 4096 where each cell has log2(order) bits. how can I convert this row. such that I will have each single bit in a seperate cell of double class. such that I will end up with a 1x(4*4096) double
Many thanks

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2012-6-23
binary = (dec2bin(bits,log2(order)) - '0') .' ;
With no cellstr()

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Data Type Conversion 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by