Store vector data of not fixed length into a Matrix

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Maximilian Arpaio
Maximilian Arpaio 2018-9-17
编辑： Maximilian Arpaio 2018-9-17
Dear community, I am trying to store different vectors 1 x N inside a Matrix M x N. The issue in doing this is that the vectors have not the same length N (which is variable for each row) and thus each row M does not have the same number of columns N. I've tried to allocate a zero matrix in advance so that deltas could have been filled in by zeros, but it is not working. How can I overcome this ?
example: A=zeros (8) A(3)=[1 2 3 4] A(1)=[2 6 7 9] A(2)=[4 6 6 7 8 9 1 3]
A(3) and A(1) assignments are returning me an error while A(2) assignment not. For those arrays < 8 elements, I was hoping to get 0s as fill ups to comply to the matrix's length.
Please advise...

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John D'Errico
John D'Errico 2018-9-17
编辑：John D'Errico 2018-9-17
You cannot store entire vectors into a double matrix as you tried to do. So this is impossible:
A(1)=[2 6 7 9]
A(2)=[4 6 6 7 8 9 1 3]
First, a flat (double precision) array cannot store multiple elements into a single element of that array. Second, an array cannot have rows (or columns) of different lengths.
You must either use a cell or struct array, or store the vectors properly inside a double array. So you COULD have done this:
A(1,1:4)=[2 6 7 9]
but then you are forced to know how long the vector is in advance.
A cell array is fully a better choice.

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