how to split one dimensional array into 3 equal chunks?

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sana3 sal
sana3 sal 2018-9-24
评论： Star Strider 2018-9-24
Hi, I have the attached data array as an example, I need to split it into 3 equal chunks! Then I need to apply that for any other array with the same type but with different length.
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Adam Danz
Adam Danz 2018-9-24
There's one variable stored in your mat file so it would be a lot simpler to help you if you just describe that variable rather than require multiple people do download a mat file, load it in matlab, etc.
The variable Cb is a column vector of length 4897 which is not divisible by 3 so it is impossible to divide it into 3 chunks of equal length.
sana3 sal
sana3 sal 2018-9-24
So, suppose it is any other array that has divisible length!?

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Star Strider
Star Strider 2018-9-24
Try this:
s = load('Cb.mat');
Cb = s.Cb;
var3c = @(oldvar) mat2cell(oldvar(:), [fix(numel(oldvar)/3) *[1, 1], numel(oldvar)-2*fix(numel(oldvar)/3)], 1); % Create New Matrix From Original Vector
newCb = var3c(Cb)
newCb =
3×1 cell array
{1632×1 double}
{1632×1 double}
{1633×1 double}
You cannot divide your vector equally, although you can get close. The ‘var3c’ anonymous function works with any length vector. It returns a cell array of 3 column vectors, even if the original vector is a row vector.
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Star Strider
Star Strider 2018-9-24
As always, my pleasure!
If it gives you the same result as I got, that would work.

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Adam Danz
Adam Danz 2018-9-24
编辑：Adam Danz 2018-9-24
This will take a column vector whose length is divisible by 3 and reshape it into a matrix with 3 columns of equal length. Each column of the new matrix will be one of your chunks.
Cb = (1:300)';
n = 3;
Cbmat = reshape(Cb, [], n);
Cbmat(:,1) is chunk 1, Cbmat(:,2) is chunk 2, etc.
This will break if Cb is not divisible by n.

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