How can I make matrix dimensions to agree?

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Dursman Mchabe
Dursman Mchabe 2018-10-9
编辑： KALYAN ACHARJYA 2018-10-9
Hi all, I get an error message:
Matrix dimensions must agree.
Error in lsqcurvefit/objective (line 279)
F = F - YDATA;
Error in snls (line 333)
newfvec = feval(funfcn{3},xcurr,varargin{:});
Error in lsqncommon (line 167)
snls(funfcn,xC,lb,ub,flags.verbosity,options,defaultopt,initVals.F,initVals.J,caller, ...
Error in lsqcurvefit (line 271)
lsqncommon(funfcn,xCurrent,lb,ub,options,defaultopt,allDefaultOpts,caller,...
Error in CurveFitting (line 135)
[theta,Rsdnrm,Rsd,ExFlg,OptmInfo,Lmda,Jmat]=lsqcurvefit(@kinetics,theta0,t,c);
when I run the attached code. What could be the cause of the disagreement?
Kind Regards Dursman

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KALYAN ACHARJYA
KALYAN ACHARJYA 2018-10-9
编辑：KALYAN ACHARJYA 2018-10-9
That means F =F-YDATA must be in the same dimension.
Please ensure that F and TDATA must be same before doing subtraction operation.
I have noticed in your code dcdt(2), dcdt(3),...what do these mean, are those scalar or vector variables?
Why you mixed up the function descriptions with other body code?
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Dursman Mchabe
Dursman Mchabe 2018-10-9
Thanks a lot for the answer.
dC = dcdt
And dcdt is a set of 7 differential equations dcdt(1) ... dcdt(7).
They are vectors.
KALYAN ACHARJYA
KALYAN ACHARJYA 2018-10-9
编辑：KALYAN ACHARJYA 2018-10-9
Welcome, @Dursman If all dcdt(1) ... dcdt(7) are calculated from the same expression, you can use the dcdt(i) indexing the way to find it.
Happy to Help

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