Generation of a matrix based on a defined order of numbers

2 次查看（过去 30 天）
Fayyaz
Fayyaz 2018-10-18
评论： Fayyaz 2018-10-22
Hi all,
I need your help regarding the generation of a set of numbers.
Suppose, I have two vectors:
v1 = [2 3 4 5 6 7 8 9]
v2 = [3 4 5 6 7]
From v1, I would like to draw five numbers such that these five numbers include only (and any) two values of v1 (always only two numbers in the sequence), i.e.,
2 2 9 9 9
3 3 7 7 7
2 9 9 9 9
.........etc
Then I would like to draw five number from v2, however, the five numbers drawn from v1 are based on only one number that is (always one number in the sequence),
3 3 3 3 3
4 4 4 4 4
........
In the end, the sequences would include 10 numbers where every sequence of the five numbers drawn from v1 are combined with every other sequence of numbers drawn from v2. That is,
2 2 9 9 9 3 3 3 3 3
2 2 9 9 9 4 4 4 4 4
2 2 9 9 9 5 5 5 5 5
. ............
I would like to find out all the combinations that are possible, i.e., starting from
2 2 2 2 3 3 3 3 3 3
2 2 2 2 3 4 4 4 4 4
2 2 2 2 3 5 5 5 5 5
2 2 2 2 3 6 6 6 6 6
2 2 2 2 3 7 7 7 7 7
.........
.......
8 9 9 9 9 7 7 7 7 7
Many thanks.

请先登录，再回答此问题。

采纳的回答

Guillaume
Guillaume 2018-10-19
One way to do it:
v1 = [2 3 4 5 6 7 8 9];
v2 = [3 4 5 6 7];
pick1 = nchoosek(v1, 2)';
idx1 = hankel([1 1 1 1 2], [2 2 2 2]) + permute(2*(0:size(pick1, 2)-1), [1 3 2]);
pick1 = reshape(pick1(idx1), 5, [])
pick2 = repmat(v2', 1, 5);
[pick2, pick1] = ndgrid(num2cell(pick2, 2), num2cell(pick1', 2));
result = cell2mat([pick1(:), pick2(:)])

更多回答（2 个）

Image Analyst
Image Analyst 2018-10-18
I believe this works:
v1 = [2 3 4 5 6 7 8 9]
v2 = [3 4 5 6 7]
% Get first vector of 5 numbers from v1.
twoIndexes = randperm(numel(v1), 2)
twoNumbers = sort(v1(twoIndexes))
index = randi(4)
firstVec = [twoNumbers(1) * ones(1, index), twoNumbers(2) * ones(1, 5 - index)]
% Get second vector of 5 numbers from v2.
secondIndex = randperm(numel(v2), 1)
secondVec = v2(secondIndex) * ones(1, 5)
% Stitch together to get the final vector.
finalVec = [firstVec, secondVec]
  3 个评论
显示 1更早的评论
Image Analyst
Image Analyst 2018-10-19
A set of for loops can do it. Can't you figure it out?
What's the use case for this? Why do you want/need to do this unusual thing?
Fayyaz
Fayyaz 2018-10-19
Thanks for the hint. I need every combination so that at the end I get 10 combinations which minimise the determinant of the asymptotic variance-covariance matrix for a utility function

请先登录，再进行评论。

Andrei Bobrov
Andrei Bobrov 2018-10-19
编辑：Andrei Bobrov 2018-10-19
v1 = [2 3 4 5 6 7 8 9];
v2 = [3 4 5 6 7];
n = numel(v2);
q = nchoosek(v1,2)';
m = reshape(permute(...
q(2 - tril(ones(n-1,n)) + reshape(0:size(q,2)-1,1,1,[])),[2,1,3]),n,[])';
v = v2(:)*ones(1,5);
n2 = size(m,1);
out = [m(kron((1:n2)',ones(n,1)),:), repmat(v,n2,1)];
Added
m = reshape(permute(q( bsxfun(@plus,2 - tril(ones(n-1,n)),...
reshape(0:size(q,2)-1,1,1,[])) ),[2,1,3]),n,[])'; % for MATLAB <= R2016a

类别

在 Help Center 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by