Hi, How to increase the line size by using a command not manually because I have many lines can't adjust each one individually. Thanks

1 次查看(过去 30 天)
for Kd=0.2:0.01:1
%for Kq=0.2:0.01:0.9
Lf=3.3e-3
Cf=100e-6
Rl=0.2
Ll=0.05
w=100*pi
%Kd=0.4
Kq=0.35
Kpdi=28
Kidi=6
Kpqi=28
Kiqi=0.2
Kpdv=5.5
Kidv=10
Kpqv=10
Kiqv=0
H=0.5
a0701=((-(w^2)*Lf*Cf)-(Kpdi*Kpdv)+(Kidi*Cf)-1)/Cf
a0702=(w*Kpdi*H)-(w*Kpdi*Kpdv*Kd)-(2*w*Kpdi)
a0703=(Kpdi+(Kpdi*Kpdv*Kd)+((w^2)*Kpdi*Lf*Cf)-(Kpdi*Kidv*Lf)-(Kpdi*H))/Lf
a0704=(2*w)-(w*Kpdi*Kpdv)
a0705=((Kpdi*Kpdv)-1)/Cf
a0707=((Kpdi*H)-(Kpdi*Kpdv*Kd)-Kpdi)/Lf
a0801=-(w*Kpqi*H)+(w*Kpqi*Kpqv*Kq)+(2*w*Kpqi)
a0802=(((w^2)*Lf*Cf)-(Kpqi*Kpqv)-(Kiqi*Cf))/Cf
a0803=(w*Kpqi*Kpqv)-w
a0804=(Kpqi+(Kpqi*Kpqv*Kq)+((w^2)*Kpqi*Lf*Cf)-(Kpqi*Kiqv*Lf)-(Kpqi*H))/Lf
a0806=(Kpqi*Kpqv)/Cf
a0808=((Kpqi*H)-(Kpqi*Kpqv*Kq)-Kpqi)/Lf
a0902=(w*H)-(w*Kpdv*Kd)-w
a0903=((Kpdv*Kd)+((w^2)*Lf*Cf)-(Lf*Kidv)-H)/Lf
a0907=(H-(Kpdv*Kd))/Lf
a1001=-(w*H)+(w*Kpqv*Kq)+w
a1004=((Kpqv*Kq)+((w^2)*Lf*Cf)-(Lf*Kiqv)-H)/Lf
a1008=(H-(Kpqv*Kq))/Lf
A1=[0 w -1/Lf 0 0 0 1/Lf 0 0 0 0 0]
A2=[-w 0 0 -1/Lf 0 0 0 1/Lf 0 0 0 0]
A3=[1/Cf 0 0 w -1/Cf 0 0 0 0 0 0 0]
A4=[0 1/Cf -w 0 0 -1/Cf 0 0 0 0 0 0]
A5=[0 0 1/Ll 0 -Rl/Ll w 0 0 0 0 0 0]
A6=[0 0 0 1/Ll -w -Rl/Ll 0 0 0 0 0 0]
A7=[a0701 a0702 a0703 a0704 a0705 w*Kpdi a0707 -w Kidi 0 (Kpdi*Kidv) 0]
A8=[a0801 a0802 a0803 a0804 -(w*Kpqi) a0806 w a0808 0 Kiqi 0 (Kpqi*Kiqv)]
A9=[-(Kpdv/Cf) a0902 a0903 -(w*Kpdv) Kpdv/Cf w a0907 0 0 0 Kidv 0]
A10=[a1001 -(Kpqv/Cf) (w*Kpqv) a1004 -w Kpqv/Cf 0 a1008 0 0 0 Kiqv]
A11=[0 -(Kd*w) Kd/Lf 0 0 0 -(Kd/Lf) 0 0 0 0 0]
A12=[Kq*w 0 0 Kq/Lf 0 0 0 -(Kq/Lf) 0 0 0 0]
A=[A1;A2;A3;A4;A5;A6;A7;A8;A9;A10;A11;A12];
D=(eig(A))/100;
GH=zpk([],D,1);
pzmap(GH);
hold on
end

采纳的回答

madhan ravi
madhan ravi 2018-10-24
Use
(...'MarkerSize',10)
inside plot command 10 denotes the size of the star
  6 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Surface and Mesh Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by