Need help for solving an Optimization problem

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VISHNUPRIYA M S
VISHNUPRIYA M S 2018-10-24
编辑： Torsten 2018-10-29
I have written a code for my problem My problem is Min L
Subject to:
0 ≤ Qt ≤ Qm
St = St-1 + It - Qt
Sd ≤ St ≤ Sm
Qt ≤ L
%Read the excel file containing time series inflow data
data = xlsread('Reservoir.xlsx');
t = data(:,1); % days
I(:,1) = data(:,2); % m^3
T = data(end,1); % days
S_0 = data(1,5); % m^3
S_d = data(2,5); % m^3
S_m = data(3,5); % m^3
Q_m = data(4,5); % m^3
L = optimvar('L',1,'LowerBound',0,'UpperBound',Q_m);
Q = optimvar('Q',T,'LowerBound',0,'UpperBound',Q_m);
S = optimvar('L',T,'LowerBound',S_d,'UpperBound',S_m);
waterbalance = optimconstr(T,1);
for t = 1:T
if t == 1
storage = S_0;
else
storage = S(t-1);
end
waterbalance(t) = S(t) == storage + I(t) - Q(t);
end
discharge = optimconstr(T,1);
for t= 1:T
discharge(t) = Q(t)<=L;
end
prob.Constraints.waterbalance = waterbalance;
prob.Constraints.discharge = discharge;
prob = optimproblem;
prob.Objective = L;
sol = solve(prob)
I need the minimized value for L. But i am getting answer as 0. Please help me.
  4 个评论
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Torsten
Torsten 2018-10-24
I always use "linprog" to solve this kind of problems.
VISHNUPRIYA M S
VISHNUPRIYA M S 2018-10-29
Can you please tell me how to use "linprog" here?

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采纳的回答

Torsten
Torsten 2018-10-29
编辑：Torsten 2018-10-29
- Take L, Qt, St as variables to be solved for.
- Define upper bounds ub and lower bounds lb to account for
0 ≤ Qt ≤ Qm
Sd ≤ St ≤ Sm
- Define matrix Aeq and vector beq to account for
St - St-1 + Qt = It
- Define matrix A and vector b to account for
Qt - L ≤ 0
- Define the vector f as (1,0,0,...,0).
- Call linprog.
Best wishes
Torsten.

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