Change values of a matrix if meet the condition

1 次查看(过去 30 天)
Hi guys a have a 2*2 matrix. and I want to substite the values of the 2 columns based in 2 different conditions. EX a= '1' '0' '0' '1'. For the first column if X=1 y=0.6 and if X=0 y=0.4. Similarly in column 2 if x=1 y=0.7 and if x=0 y=0.3. Therefore, new matrix b= '0.6' ' 0.4' '0.3' '0.7'.

回答(1 个)

James Tursa
James Tursa 2018-11-2
编辑:James Tursa 2018-11-2
E.g., I think this is what you are asking for:
a = your matrix of 1's and 0's
p = your matrix of values (1st row corresponding to 0 values, 2nd row corresponding to 1 values)
c = 1:size(a,1):numel(a); % Set up for linear indexing
b = a; % An arbitrary matrix the same size as a
b(:) = p(bsxfun(@plus,a,c)); % Replace elements with appropriate p values (linear indexing)
On later versions of MATLAB you don't need bsxfun:
b(:) = p(a+c); % Replace elements with appropriate p values (linear indexing)
A sample run:
>> a = eye(2)
a =
1 0
0 1
>> p = [0.4 0.3; 0.6 0.7]
p =
0.4000 0.3000
0.6000 0.7000
>> c = 1:size(a,1):numel(a)
c =
1 3
>> b = a
b =
1 0
0 1
>> b(:) = p(bsxfun(@plus,a,c))
b =
0.6000 0.3000
0.4000 0.7000

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by