How can I calculate the area between two curves?

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Marko Boskovic
Marko Boskovic 2018-11-4
回答： madhan ravi 2018-11-4
I heave a problem, a need to calculate area between two curves, but one curve is too complicate (y1=(100./0.93).*(((x./19).^(10))./(1+(x./19).^(10))).*exp(-x./485), another curve is constant curve (y2=5). How I can calculate area between them?

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采纳的回答

Rik
Rik 2018-11-4
The polyarea function handles this just fine.
figure(1),clf(1)
x=0:1500;
y1=@(x)(100./0.93).*(((x./19).^(10))./(1+(x./19).^(10))).*exp(-x./485);
y2=@(x)5*ones(size(x));
plot(x,y1(x),x,y2(x))
Y=y1(x)-y2(x);
Y1=Y;
Y2=Y;Y2(Y2<0)=0;
Y3=abs(Y);
fprintf('A=%.0f (y2<y1 counting as negative)\n',polyarea(x,Y1))
fprintf('A=%.0f (y2<y1 not counting)\n',polyarea(x,Y2))
fprintf('A=%.0f (y2<y1 as well)\n',polyarea(x,Y3))

更多回答（1 个）

madhan ravi
madhan ravi 2018-11-4
Answer taken from star strider:
x=0:10000;
y2=repmat(5,1,numel(x));
y1=(100./0.93).*(((x./19).^(10))./(1+(x./19).^(10))).*exp(-x./485);
x = 1:numel(y1); % Use The Appropriate Vector For The Most Accurate Results
hbar = min([y1; y2]); % Denoted By Horzontal Bars
vbar = max([y1; y2]) - hbar; % Denoted By Vertical Bars
Area = trapz(x,vbar) / (trapz(x,vbar) + trapz(x,hbar))

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