Replace Nan with previous numbers
显示 更早的评论
Hello there , I have a Variable of type double with natural gas Prices that contains Nans for dates that I don't have data and i want to replace Nans with the previous day known price. I tried function "fillts" but i didn't got what I wanted to . I appreciate any help Thanks in advance
data = [...
7.51
NaN
NaN
7.61
NaN
NaN
7.85];
采纳的回答
Andrei Bobrov
2012-7-5
编辑：Andrei Bobrov
2012-7-5
t = ~isnan(data);
a = data(t);
out = a(cumsum(t));
ADD on Aggelos's comment
t = ~isnan(data);
idx = cumsum(t);
idx(~idx) = 1;
a = data(t);
out = a(idx);
更多回答（3 个）
Image Analyst
2012-7-5
Try this:
m = [nan 2 3 4 nan 6 7 nan 9] % Sample data
indexes = find(isnan(m))
if ~isempty(indexes)
% Handle case where first index is nan - get rid of it.
if indexes(1) == 1
m = m(2:end);
indexes = indexes(2:end) - 1
end
% Take prior index if element is nan.
m(indexes) = m(indexes-1)
end
2 个评论
aggelos
2012-7-5
Image Analyst
2012-7-5
编辑：Image Analyst
2012-7-5
You did something wrong, because I just copied and pasted my code on another computer and it worked great here also.
Plus you still need to say what you want done in case the first element is a nan. andrei and my vectorized solutions chose to handle it in different ways, while John non-vectorized code assumed that you would never have such a case (a non-robust, risky assumption). andrei's code seems to be even more robust than mine because his handles sequences of multiple nans in a row while mine doesn't. But his takes the second element for the first output element if the first input element is a nan, while mine just throws it away and shortens the array - that's why I asked what you want to do in such a case.
John
2012-7-5
try the following:
x = isnan(data);
for i = length(data)
if x(i) == 1
data(i) = data(i-1);
end
end
Chad Greene
2014-11-1
repnan can do it by
data = repnan(data,'previous');
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