How to select one number from a loop. I want to calculate the time t when m5=99.9. when I run the program it doesn't show anything. I don't know how to print t from the time loop when m5=99.99

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dt = 0.01; % Step size
tend = 50; % End time
t = 0:dt:tend; % Time vector
%Loop for m5 calculation
for i=1:(length(t)-1)
for j=1:length(i)
k1 = f5(t(i),m5(i));
k2 = f5(t(i)+0.5*dt,m5(i)+0.5*dt*k1);
k3 = f5((t(i)+0.5*dt),(m5(i)+0.5*dt*k2));
k4 = f5((t(i)+dt),(m5(i)+k3*dt));
end
m5(i+1) = m5(i) + (1/6)*(k1(j)+2*k2(j)+2*k3(j)+k4(j)).*dt;
if m5==99.9
break
fprintf('%d',t(i))
end

采纳的回答

the cyclist
the cyclist 2018-11-8
编辑:the cyclist 2018-11-8
The reason you don't an exact match has to do with the representation of floating point numbers.
Instead of testing with
if m5==99.9
try
tol = 1.e-5;
if abs(m5-99.9) < tol

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