I have a matrix of 4095 by 4. i need to divide it into submatrices of 117 by 1.

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Sajid Sarwar 2018-11-9

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https://ww2.mathworks.cn/matlabcentral/answers/428876-i-have-a-matrix-of-4095-by-4-i-need-to-divide-it-into-submatrices-of-117-by-1

评论： Walter Roberson 2018-11-19

How can I do this using for loop? I mean I have to select first 117 rows and 1st column then first 117 rows and 2nd column, then first 117 rows and 3rd column and then 1st 117 rows and 4th column. after that repeat this for next 117 rows and so on uptill 4095 rows.

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Walter Roberson 2018-11-9

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在 MATLAB Online 中打开

Baserow = (column-1) * 117;
Subset = YourImage(Baserow+(1:117),column, :) ;

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Sajid Sarwar 2018-11-19

编辑：Walter Roberson 2018-11-19

在 MATLAB Online 中打开

txSig(n, n1, :) = ofdmMod(Subset);

by this line I'm getting txSig in 3 dimensions whereas I need 2D data for further use in y = awgn(txSig, SNR(k));

and sigRx = ofdmDemod(y);

Walter Roberson 2018-11-19

在 MATLAB Online 中打开

You do not need 2D data for awgn. You might need a row vector for ofdmDemod though.

st=rand(9945,4)
for n=1:85
  Baserow = (n-1) * 117;
  for n1 = 1:4
    Subset = st(Baserow+(1:117),n1, :)
    txSig(n, n1, :) = ofdmMod(Subset);                      
    y = awgn(txSig(n, n1, :), SNR(k));
    sigRx(n, n1, :) = ofdmDemod(y(:).');
   end
end