How to remove a bracketed number from a cell array while leaving the number in front of it alone

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Robert Garneau
Robert Garneau 2018-11-11
评论： Robert Garneau 2018-11-11
Hi, I have a cell array called "mycellarray" with the following types of strings in it: 24[13]
The [13] in this case is a reference to a footnote and I want to remove the [13] and just have the number 24 left. How do I use a regular expression to remove "[13]" or any footnote i.e. [3] from the number.
Example of the contents of the cell array
13.4[5]
24[11]
56.99[23]
22[4]
I want to remove all the bracketed values along with the number inside the brackets and just have the double number in front kept in the cell array Thank you for your help.. Bob

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采纳的回答

Walter Roberson
Walter Roberson 2018-11-11
newstring = regexprep(oldstring, '\[\d+\]', '') ;

更多回答（1 个）

madhan ravi
madhan ravi 2018-11-11
编辑：madhan ravi 2018-11-11
see https://www.mathworks.com/matlabcentral/answers/287644-removing-square-brackets-from-string
https://www.mathworks.com/matlabcentral/answers/215551-removing-square-brackets-from-cell-array#answer_178209
mycellarray={'24[13]'}
regexprep(mycellarray, '\[(.*?)\]', '$1') %edited after sir Walter's comment
or
A='13.4[5] 24[11] 56.99[23] 22[4]'
A(A=='[') = [];
% Remove any and all right brackets.
A(A==']') = []

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