Detecting Remainder Starts and Ends when Gaps are Present

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Midimistro 2018-11-15

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/430083-detecting-remainder-starts-and-ends-when-gaps-are-present

Say I have an array known as divideRem that is a result of using rem(A,B) where A is a vector that is always counting up but contains gaps in certain places that have no set gap size such that:

A= [2821,2822,2823,2824,2825,2827,2830,2831,2832,2836,2839,2841,2842,2843,2844,2845,2861,2862,2863,2864,2865,2866,2867,2881,2885,2888,2891,2892,2893,2894,2901,2921,2922,2923,2924,2925];
B=10;
divideRem=rem(A,B)
%thus: 
% divideRem=[1,2,3,4,5,7,0,1,2,6,9,1,2,3,4,5,1,2,3,4,5,6,7,1,5,8,1,2,3,4,1,1,2,3,4,5];

What is the most effective way to detect/find where the start (aka divideRem==1 or smallest value that is not 0) and end of the repeating series (highest value or divideRem==0) that occurs in divideRem such that the resulting truth vectors are found to be:

divRemStart=[1,0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,1,0,0,1,0,0,0,1,1,0,0,0,0];
divRemEnd=[0,0,0,0,0,0,1,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,1,0,0,1,0,0,0,1,1,0,0,0,0,1];

Notes:

1 may not always be the start (as seen above),
0 might not always be the end (as seen above),
and that if (A(i)-A(i+1)>10), the divideRem(i) and divideRem(i+1) will not be part of the same start/end set;

The end goal is to create start/end sets of equal sizes.

Any ideas?