Why does the output of a discrete transfer function goes NaN?
7 次查看(过去 30 天)
显示 更早的评论
My simulink model has a discrete transfer function block.The numerator and the denominator are given externally because their coefficients change as the simulation runs.What are the possible reasons for the output of the discrete transfer function to go NaN?What are the possible soultions to solve the same?
3 个评论
Walter Roberson
2022-7-14
You have infinity or negative infinity in the input signal, and you do not happen to have the situation where all non-zero coefficients appear only in even powers.
For example negative infinity and coefficients [1 1 1] would be 1*(-inf)^2 + 1*(-inf) + 1 which would be (inf) + (-inf) + 1 and inf - inf is nan.
Rahul Shinde
2022-7-15
Many thanks for your response @Walter Roberson. After your hints I was able to focus & identify the issue in my model.
Good day.
回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 General Applications 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!