1D series to 2D stacked

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Hi,
I`m trying to think in a best option to "convert" a 1d arrays to a 2d as follows:
B has a fixed size of 10000x(a prior know number, here 6), so it just need to stack number 1's regarding the number into the aray A.
A =
1 5 3 1 2 4
B =
....
....
....
0 1 0 0 0 0
0 1 0 0 0 1
0 1 1 0 0 1
0 1 1 0 1 1
1 1 1 1 1 1 % ROW 1
It can be done maniulating the arrays in a slow way, I would like to do much faster.
Thanks
  2 个评论
Kevin Chng
Kevin Chng 2018-11-27
Hi,
to stack number 1's regarding the number into the aray A?Do you mind to elaborate the relationship between A and B?
Walter Roberson
Walter Roberson 2018-11-27
Kevin, read the output B from the bottom upwards. The first column has one 1, which is the same number as A(1). The second column has five 1, which is the same number as A(2). And so on. So if you were to sum(B) then you would get A, with it always being the last so-many entries that are set to 1.

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采纳的回答

Stephen23
Stephen23 2018-11-27
编辑:Stephen23 2018-11-27
In one line:
B = A>=(10000:-1:1).'
Or for versions prior to R2016b:
B = bsxfun(@ge,A,(10000:-1:1).');

更多回答(1 个)

Walter Roberson
Walter Roberson 2018-11-27
t = fliplr(1 : 10000);
B = t.' <= A;
This requires R2016b or later. For earlier releases, change the B line to
B = bsxfun(@le, t.', A);

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