How to check the number of ones from certain row to the 1st row?
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t(:,:,1) =
1 10 19 28 37 46 55 64 73 82
2 11 20 1 38 47 56 65 74 83
3 12 21 30 39 48 57 66 75 84
4 13 22 31 40 49 58 67 76 85
5 14 1 32 41 50 59 68 77 86
6 15 24 33 42 51 60 69 78 87
7 16 25 34 43 1 61 70 79 88
8 17 26 35 44 53 62 71 80 89
9 18 27 36 45 54 63 72 81 90
t(:,:,2) =
91 100 109 118 127 136 145 154 163 172
92 101 110 119 128 137 146 155 164 173
93 102 111 120 129 138 147 156 165 174
94 103 112 121 1 139 148 157 166 175
95 104 1 122 131 140 149 158 167 176
96 105 114 123 132 141 150 159 168 177
1 106 115 124 133 142 151 160 169 178
98 107 116 125 134 143 152 161 170 179
99 108 117 126 1 144 153 162 171 180
How to check the number of ones but starting from row 7 till the 1st row for both matrices?
Is it using for loop ?
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Walter Roberson
2018-11-27
squeeze( sum( t(1:7, :, :) == 1, 1 ) )
the result would be 10 x 2 -- the 10 columns of t and the 2 panes.
3 个评论
Image Analyst
2018-11-27
Gvie numerical example, including both inputs and the desired output.
I don't even know what "row 7 till the 1st row" means. Doesn't really make sense in English. "till" usually means "until". So "row 7 until..." would mean from row 7 (inclusive) until some row larger than 7, like 8, 9, 100, etc. NOT row 1, which is in the backward/smaller direction.
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