sampled signal fft signal

6 次查看(过去 30 天)
hi,i have a task that i dont get it how to be done.
i have sampled ecg signal with fs=1024 hz (vector )
the task is to plot the pulses per minute (1/min) of the ecg signal
s1 is the sampled vector
b=fft(s1)
a=length(s1)
w=0:(2*pi/a):2*pi*(a-1)/a)
well the axix on w,how the fs get in the work ,it must be that i need changing 1 min= 60s=60000ms
please help
i.e the signal is harmonic signal with doubles frequencies of the original frequency signal

采纳的回答

David Goodmanson
David Goodmanson 2018-11-30
Hi yuval,
You don't have to bother with omega since the fft operates with straight frequency. I arbitrarily picked the number of points for a data set, and you supplied fs.
N = 10000;
fs = 1024;
delt = 1/fs; % time array spacing, by definition
t = (0:N-1)*delt;
For the frequency array, the following is always true for ffts:
delf = fs/N; % frequency array spacing (Hz), fft rule
f = (0:N-1)*delf;
Now for the fft and rescaled frequencies. The frequency spectrum plot is done in the usual way by taking absolute value, plotting positive frequencies only and doubling the result except fot the dc term. You will see peaks at 120 and its harmonics.
% first, make up some data, 120 bpm = 2 bps
f0 = 2;
y = exp(-10*mod(t,1/f0)+(.4)*rand(1,N));
figure(1)
plot(t,y)
% ----------------
% frequency domain calc
z = fft(y)/N;
f = f*60; % rescale frequencies from per sec to per min <==
% plot
halfN = floor((N+1)/2);
f_plot = f(1:halfN);
absz_plot = abs(z(1:halfN));
absz_plot(2:end) = 2*absz_plot(2:end); % don't double f = 0 (dc)
figure(2)
plot(f_plot,absz_plot)
xlim([0,1200]) % optional
(Technically if N is even you should not double the last element in absz_plot either, but I will not hassle with that detail here. The whole process of half the frequencies, abs, double, etc. kind of sucks anyway).
  6 个评论
yuval ohayon
yuval ohayon 2018-12-1
f=(0:a-1)*(fs/N) %%fft rule fs/n array
F_W=fft(s1)/N %%normelaize amplitude
F_per_min=f*60 %%rescale bps to bpm
b=floor(a+1)/2
b_axix=F_per_min(1:b)
Y_axix=abs(F_W(1:b))
figure(2)
plot(b_axix,Y_axix)
xlim([0 2000])
xlabel('bpm[rad/min]')
ylabel('F_W(ecg(w)')
yuval ohayon
yuval ohayon 2018-12-1
david,why its neccesery changing a=length(s1)====>b,why i shorted the w axix by 2?
thats the diffference?
(if only need to change the f =60*f and normelaiz amplitude)

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Fourier Analysis and Filtering 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by