Error "Could not open file 'ncfiles'". when using a for loop to open ncfiles

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Jonas Damsbo
Jonas Damsbo 2018-12-3
评论： Walter Roberson 2018-12-7
Hi
I have 469 ncfiles and I open them in a loop:
ncfiles = dir('*.nc') ;
Nfiles = length(ncfiles) ;
for i = 1:Nfiles;
ncdisp(ncfiles(i).name) ;
ncid=netcdf.open('ncfiles','NOWRITE');
varname = netcdf.inqVar(ncid);
[ndim, nvar, natt, unlim]=netcdf.inq(ncid);
end
But when I run the code I got the error when I used ncid:
Error using netcdf.open (line 52)
Could not open file 'ncfiles'.
Error in Blocking (line 9)
ncid=netcdf.open('ncfiles','NOWRITE');
I hope you can help me!

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采纳的回答

Walter Roberson
Walter Roberson 2018-12-3
your file name is stored in ncfiles(i).name rather than being the literal file name 'ncfiles'
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Jonas Damsbo
Jonas Damsbo 2018-12-7
Such like that?
%Indlæser alle filer fra folderen
ncfiles = dir('*.nc') ;
Nfiles = length(ncfiles) ;
for i = 1:Nfiles;
ncdisp(ncfiles(i).name) ;
ncid=netcdf.open(ncfiles(i).name,'NOWRITE');
%[ndim, nvar, natt, unlim]=netcdf.inq(ncid);
netcdf.close(ncid);
end
lat = cell(Nfiles, 1);
lon = cell(Nfiles, 1);
time = cell(Nfiles, 1);
z = cell(Nfiles, 1);
for i = 1:Nfiles
lon(i) = ncread(ncfiles(i).name, 'longitude'); %nx = length(lon(i));
lat(i) = ncread(ncfiles(i).name, 'latitude'); %ny = length(lat(i));
time(i) = ncread(ncfiles(i).name, 'time'); %nt = length(time(i));
z(i) = ncread(ncfiles(i).name, 'z'); %nz = length(z(i));
end
Because now I get the error "Conversion to cell from single is not possible."

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