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accelerating code , scalar operations

1 次查看（过去 30 天）
Sara
Sara 2012-7-11
关闭： MATLAB Answer Bot 2021-8-20
Hi Guys,
if k <= 0
int = x ;
return
end
int = zeros(1,length(x));
c=(k-1)/factorial(k-1);
dth2=dt/2;
lenx=length(x);
ft1=(lenx:-1:0)*dt;
for n = 3:lenx
y1 = x(2:n) ;
t1 = ft1(lenx-n+3:lenx+1) ;
y2 = x(1:n-1) ;
t2 = t1 +dt;
int(n) = sum (t1.^c.*y1 + (t2.^c).*y2)*dth2 ;
end
Is there any way to do .^c in the line ft1=(length:-1:0)*dt which is before and out of the for loop and get the same result as above code? Any suggestion would be appreciated.

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