Checking/Counting values in a given Timewindow

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JamJan
JamJan 2018-12-11
编辑： TADA 2018-12-11
In the following Matrix I have the following '1' states according to their positions:
1 1174 1175 2006 2007 2809 2810 3670 3671 4541 4542 5265 5266 6139 6140 6584 6585 6856 6857 7646 7647 8382 8383 9142 9143
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
However, I have certain Timewindows for example:
1280,5 2560,5 3840,5
Now I want to check how many 1's are within this Time Window (1280,5 - 3840,5)
How can I do this?

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TADA
TADA 2018-12-11
编辑：TADA 2018-12-11
I'm not sure what the ",5" stand for in your time frame, but you can do something like that:
states = [1 1174 1175 2006 2007 2809 2810 3670 3671 4541 4542 5265 5266 6139 6140 6584 6585 6856 6857 7646 7647 8382 8383 9142 9143;
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1];
% define time window
tw = [1280, 3840];
% if the '1' states are either 1 or 0 you can sum them up like that:
numOnes = sum(states(2, states(1,:) >= tw(1) & states(1,:) <= tw(2)))
numOnes =
6
% otherwise, you can count the ones more specifically:
numOnes = sum(states(2, states(1,:) >= tw(1) & states(1,:) <= tw(2)) == 1)
numOnes =
6

更多回答（1 个）

Gareth
Gareth 2018-12-11
Hi JamJan,
If I understand correctly you have a matrix with 2 rows, the first row shows times, and the second 1. You are asking to count how many ones between a certain time range.
Here is an example on how to do this: (where I am using larger than 6, and smaller than 23)
a = [ 1:4:40; ones(1,10)]
idx = a(1,:)>6 & a(1,:)<23
sum(a(2,idx))
This uses logical indexing.
I hope this makes sense to you and you can apply this to your case.

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