how to lapace results
1 次查看(过去 30 天)
显示 更早的评论
how to plot this please
deqdiff = 'diff(y(t),t,t) + y(t) - cos(t)'
ldeqdiff = laplace(deqdiff,t,s)
sldeqdiff = subs(ldeqdiff,{'D(y)(0)','y(0)'},{1,1})
syms Ys
ldeqinit = subs(sldeqdiff,'laplace(y(t),t,s)',Ys)
ly = solve(ldeqinit,Ys)
ilaplace(ly,s,t)
0 个评论
采纳的回答
Walter Roberson
2018-12-13
syms s t y(t)
Dy = diff(y);
deqdiff = diff(y(t),t,t) + y(t) - cos(t);
ldeqdiff = laplace(deqdiff,t,s);
sldeqdiff = subs(ldeqdiff,{Dy(0), y(0)},{1,1});
syms Ys
Lyt = laplace(y(t), t, s);
ldeqinit = subs(sldeqdiff, Lyt, Ys);
ly = solve(ldeqinit,Ys);
ily = ilaplace(ly,s,t);
fplot(ily, [0 20])
4 个评论
Walter Roberson
2018-12-13
You are using the transition release, when fplot had been introduced but did not yet support symbolic expressions.
Replace
fplot(ily,[0 20])
with
Fily = matlabFunction(ily);
fplot(Fily, [0 20])
.... And laplace still is not documented in your release (or any other release) as accepting a character vector. You need to start using documented behaviour or else we are going to start telling you to work things out by yourself since you are relying on undocumented behaviour.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Assumptions 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!