Symbolic Expression Sum Same Denominator

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I have a symbolic experssion in the form: (where are symvars)
(3*a)/8 + (3*b)/8 + c/4
I would like this to be in the form of the same denominator, like:
(3*a + 3*b + 2*c) / 8
How can I achieve this ?

回答(2 个)

Star Strider
Star Strider 2018-12-26
编辑:Star Strider 2018-12-26
Try this:
syms a b c
Eqn = (3*a)/8 + (3*b)/8 + c/4
[Eqnn,Eqnd] = numden(Eqn)
producing:
Eqnn =
3*a + 3*b + 2*c
Eqnd =
8
Unfortunately, if you express it again as:
NewEqn = Eqnn / Eqnd
the result is the original format for ‘Eqn’.
EDIT —
The best you can hope for is a LaTeX expression for your fraction:
syms a b c
Eqn = (3*a)/8 + (3*b)/8 + c/4
[Eqnn,Eqnd] = numden(Eqn)
fn = latex(Eqnn);
fd = latex(Eqnd);
Expr = sprintf('$f(a,b,c) = \\frac{%s}{%s}$', fn, fd)
producing:

madhan ravi
madhan ravi 2018-12-26
编辑:madhan ravi 2018-12-26
syms a b c
eqn = (3*a)/8 + (3*b)/8 + c/4
simplifyFraction(eqn,'Expand',1) % the best way to simplify a fraction by expanding also returns the same
  2 个评论
Miraç Gülgönül
Miraç Gülgönül 2018-12-26
编辑:Miraç Gülgönül 2018-12-26
I don't understand, this outputs
eqn =
(3*a)/8 + (3*b)/8 + c/4
ans =
(3*a)/8 + (3*b)/8 + c/4
so no change.
madhan ravi
madhan ravi 2018-12-26
编辑:madhan ravi 2018-12-26
Yes exactly matlab is not able to compute those fractions as you desire.
Try:
bb=factor(eqn) % gives your partial result though
Gives:
bb =
[ 1/8, 3*a + 3*b + 2*c]

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