if in a row i am having 6 numerical values of large number i want convert into binary form of length 10 bits

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rajesh kumar 2018-12-28

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评论： Walter Roberson 2018-12-30

in a row for example 4351 890 2312 9045 234 50 i want to convert into binary form with length of 10 bits, generally i can use dec2bin code but getting for one numerical value i want to get to all six numerical

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Stephen23 2018-12-30

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>> V = [234,567,123,456,900,190];
>> M = dec2bin(V(:),10)
M =
0011101010
1000110111
0001111011
0111001000
1110000100
0010111110

Each row represents one of the input numbers.

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rajesh kumar 2018-12-30

thanq

Walter Roberson 2018-12-30

Note the result will be a char array. Those 0 and 1 that show up are '0' and '1' not numeric 0 and 1. Using '0' and '1' is fine for a number of purposes, but using numeric 0 and 1 is more versatile.

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Walter Roberson 2018-12-28

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reshape((dec2bin(theVector,10)-'0').', 1, [])

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rajesh kumar 2018-12-30

my question is how to convert into bianry form and how to store in avariable

Walter Roberson 2018-12-30

The code I gave converts them values to binary with length 10 bits, and puts the result all in one vector, which is what people usually want to do when they convert a vector of numbers.

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