Can you find the error in this code that aims to sum the digits of a string?

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GEORGIOS BEKAS
GEORGIOS BEKAS 2019-1-6
编辑： Stephen23 2019-1-6
I wrote this code in order to sum the digits of any string, and to also create a loop that stops the summing process when the length of the sum is equal to a single digit.
What's wrong?
n = '12361927'
function d = sumdigits(n)
s=0
for i=1:length(n)
s=s+str2double(n(i))
end
end
s=sumdigits(n)
if length(str2num(s))==1
s=s
else
while length(str2num(s))~=1
if length(str2num(s))==1
break
else
s=sumdigits(s)
end
end
end

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采纳的回答

Stephen23
Stephen23 2019-1-6
Simpler:
str = '12361927'
while numel(str)>1
num = sum(str-'0')
str = num2str(num)
end
Prints this in the command window:
str = 12361927
num = 31
str = 31
num = 4
str = 4
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Stephen23
Stephen23 2019-1-6
编辑：Stephen23 2019-1-6
str-'0'
subtracts the character code for '0' (which is 48) from the character codes of the character array str. If all of the characters in str are digits then it converts the chracter representation of those digits into their numeric values, e.g.:
>> '1234'-'0'
ans =
1 2 3 4

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更多回答（1 个）

Stephan
Stephan 2019-1-6
Hi,
try :
n = '12361927'
s=num2str(sumdigits(n))
if strlength(s)==1
s=s;
disp('here')
else
while strlength(s)~=1
if strlength(s)==1
break
else
s=num2str(sumdigits(s))
end
end
end
function d = sumdigits(n)
s=0;
for i=1:length(n)
s=s+str2double(n(i));
end
d=s;
end

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