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Whys isn't this if working?

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Daniel Fonsêca
Daniel Fonsêca 2019-1-7
编辑： Stephan 2019-1-7
I have this code:
if intervalo & quant == 0 %Caso seja um número
intervalo = str2num(nome);
quant = 1;
end
But, it isn't working. When this condicion is true, it doesn't work.
I'm using the '&' because I need to analyze vectores. Sometimes, intervalo is vectors, so I need to use that.
Thanks by the attention.
  1 个评论
Daniel Fonsêca
Daniel Fonsêca 2019-1-7
编辑：per isakson 2019-1-7
I changed the value to 1, i say:
if intervalo & quant == 1 %Caso seja um número
intervalo = str2num(nome);
quant = 1;
end
And it worked. Why?

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Stephan
Stephan 2019-1-7
编辑：Stephan 2019-1-7
Hi,
consider:
>> intervalo = 0
intervalo =
0
>> quant = 0
quant =
0
Now case 1 - what you told Matlab to check:
>> intervalo & quant == 0
ans =
logical
0
Now the way what you problably wanted Matlab to do:
>> intervalo == 0 & quant == 0
ans =
logical
1
In other words:
If you write it the way you dit, it is the short way to write:
intervalo == 1 & quant == 0
is the same as:
intervalo & quant == 0
You got it?
Best regards
Stephan

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