Preallocate memory for a cell of structures

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John
John 2019-1-10
编辑： Stephen23 2019-1-10
What is the correct syntax to preallocate memory for the cell x in the following?
N = 10;
for n = 1:N
numRows = ceil(100*rand);
x{n}.field1 = 1*ones(numRows,1);
x{n}.field2 = 2*ones(numRows,1);
x{n}.field3 = 3*ones(numRows,1);
end
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Stephen23
Stephen23 2019-1-10
编辑：Stephen23 2019-1-10
@John: is there a specific requirement to use a cell array of structures? From the code that you have shown, a single non-scalar structure would likely be a better choice:
https://www.mathworks.com/help/matlab/matlab_prog/access-multiple-elements-of-a-nonscalar-struct-array.html

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回答（1 个）

Guillaume
Guillaume 2019-1-10
Just preallocating the cell array:
x = cell(1, N);
for ...
There wouldn't be much point preallocating the scalar structures inside each cell, particularly if you did it naively using repmat as they would be shared copy which would need deduplicating at each step of the loop. You could preallocate the structures inside the loop. For a structure with 3 fields, there wouldn't be much benefit:
x = cell(1, N);
for n = 1:N
x{n} = struct('field1', [], 'field2', [], 'field3', [])
x{n}.field1 = ...
end
But you may as well fill the structure directly with:
x = cell(1, N);
for n = 1:N
numRows = ceil(100*rand);
x{n} = struct('field1', 1*ones(numRows,1), 'field2', 2*ones(numRows,1), 'field3', 3*ones(numRows,1))
end
However, instead of a cell array of scalar structures you would be better off using a structure array:
x = struct('field1', cell(1, N), 'field2', [], 'field3', []) %creates a 1xN structure with 3 empty fields
for n = 1:N
x(n).field1 = ...
x(n).field2 = ...
x(n).field3 = ...
end

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