Initialization of array of structure

Hello
I have a created array of structure (named LD) which incrementes from 1 to no of database (eg LD(1) to LD(10)). The structure has some fields. After some time I need to re-initialise the structure.
I tried with following commands.
LD = [];
But, I lost the field names, how to initialise with out loosing the field names.

 采纳的回答

Experiment with
LD = LD(false);

4 个评论

Hello Walter, many thanks for your help!!
It works perfect to re-initialise whole set of database. If I want to delete particular database in-between, how to modify the above code.
for example LD(1)-LD(10) array of structure exists,
remove LD(4), it has
LD(4).field1
LD(4).field2
LD(4).field3
LD(4).field4
so that my final database size is LD(1) - LD(9)
Hi Walter
I think LD(4) = [] should work, please correct me if I am wrong
For the clearing, you might be able to use
LD(:) = [];
Unfortunately I cannot test that at the moment.

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更多回答(2 个)

Nirmal
Nirmal 2012-7-19
You shouldnt do LD=[], instead you should change the field of each of the structure in the array.
The following code should do the trick:
function is = StructInit(s)
is = s;
if isstruct(s)
f = fields(s);
for i = 1 : length(f);
if isstruct(is.(f{i}))
is.(f{i}) = StructInit(is.(f{i}));
else
is.(f{i}) = [];
end
end
else
is = [];
end
end
Here is an example how to use it:
% Create dummy structure.
a.a = 1;
a.b = '';
a.c = {};
a.d.a.a = 2;
a.d.a.b = 1;
a.d.b = {};
initialisedStruct = StructInit(a);
All the fields are initialised to []. If a field is a structure, that structure's fields will be initialised etc.
Conrad

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