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Skipping elseif when first condition is true

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g
g 2019-1-21
回答： Steven Lord 2019-1-21
I currently have the following scheme:
if (a =0)
q = 4
elseif (b=0)
q = 5
rest of code
end
The problem is, in the case a =0 the program does not work properly, as it simply skips the "rest of code".
I have tried moving the "end" before rest of code, but that does not work for the purposes of this.
Is there a way such that in the case a =0, it sets q=4, then just doesn't consider the elseif (b=0) case and continues onto the rest of the code?
Thanks!
  1 个评论
Stephen23
Stephen23 2019-1-21
编辑：Stephen23 2019-1-21
"The problem is, in the case a =0 the program does not work properly"
Read the MATLAB documentation to learn what operator to use for logical equivalence:
https://www.mathworks.com/help/matlab/ref/eq.html
And for other logical operators:
https://www.mathworks.com/help/matlab/relational-operators.html
Guessing is not a very efficient way to write code.

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回答（2 个）

Image Analyst
Image Analyst 2019-1-21
That's not how you check if a equals zero. You need to use double equals. A single equals is assignment, NOT comparison. Try this:
if (a == 0)
q = 4
elseif (b == 0)
q = 5
rest of code
end
Steven Lord
Steven Lord 2019-1-21
If you want to execute the rest of the code regardless of whether a was equal to 0 or b was equal to 0, take it out of the if / elseif / end block entirely.
if (a ==0)
q = 4
elseif (b==0)
q = 5
end
rest of code
If you need to throw an error if neither a nor b was 0, use else and throw an error inside the else.
if (a ==0)
q = 4
elseif (b==0)
q = 5
else
error('Expected either a or b to be 0')
end
rest of code

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