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taylor series expansion help

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Marina Christakos
Marina Christakos 2019-1-25
评论： Walter Roberson 2019-1-25
syms x
valuex=input('What is the value of x? ')
subs(taylor(exp(x),x, 'OrderMode','Relative','Order',valuex), valuex)
I need to modify my solution above so that, as well as computing and displaying the result of the Taylor series expansion, it also computes and displays the number of terms required for the approximation to be accurate to within 0.01.
The Taylor series for the exponential function e^x is 1 + (x^1)/1! + (x^2)/2! + (x^3)/3 ...
  2 个评论
Rik
Rik 2019-1-25
This is probably easiest to solve by not using symbolic variables, but using an explicit loop instead.
Walter Roberson
Walter Roberson 2019-1-25
? To confirm, the x that you evaluate the taylor series at, is to be the same as the Order (that is, the highest power to be used in the series) ??

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