Split numeric values of vector with NaN to individual matrices
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Hi all,
I have the following vector:
M = [ 1 ; 2 ; 4 ; 4 ; 2 ; Nan ; NaN ; NaN ; 2 ; 4 ; 2 ; 1 ; NaN ; 2 ; 3 ; 2 ; NaN ; NaN] ;
In words, it is a vector with numbers, and consecutive rows of NaN.
I would like to know if there is a function or a quicker way that splits the above vector in to discrete vectors inclusive of only the numeric values, leaving out the NaNs. In the case of the above vector, it could be a cell array for example, such that:
C = [{1 ; 2 ; 4 ; 4 ; 2} ; {2 ; 4 ; 2 ; 1} ; {2 ; 3 ; 2} ] ;
I have managed to make the above happen using indexing but its quite an inefficient method (15lines of code) and it doesn't perform always as expected.
Any Ideas?
KR,
KMT
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madhan ravi
2019-1-26
编辑:madhan ravi
2019-1-26
Note: In your question the first NaN should be NaN not Nan because NaN is valid in Matlab.
M = [ 1 ; 2 ; 4 ; 4 ; 2 ; NaN ; NaN ; NaN ; 2 ; 4 ; 2 ; 1 ; NaN ; 2 ; 3 ; 2 ; NaN ; NaN] ;
index=find(~isnan(M));
idx=find(diff(index)~=1);
A=[idx(1);diff(idx);numel(index)-idx(end)];
C=mat2cell(M(~isnan(M)),A,1);
celldisp(C)
Gives:
C{1} =
1
2
4
4
2
C{2} =
2
4
2
1
C{3} =
2
3
2
1 个评论
puccapearl
2024-4-17
This works great! Could you explain what the code is doing, line by line? Thanks!
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