Calling data with using rand command

Hi, I want to call data in the matrix by using string which is defined by rand command.
A=[1 2]
B=[2 3]
C=[3 5]
corners = 'ABC'
randompick = corners(randi(numel(corners)))
disp(randompick)
randompick(1)
Here I cant get any first row numbers of the A, B, and C.
What's wrong in this script?
Thanks.
Desired answer is
Same as what A(1), B(1) or C(1) give after randomly chosing.

2 个评论

what‘s the desired output?
Same as what A(1), B(1) or C(1) give after randomly chosing.

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 采纳的回答

A=[1 2
2 3
3 5] ;
corners = 1:size(A,1) ;
randompick = corners(randi(numel(corners)))
disp(randompick)
idx = randompick(1) ;
iwant = A(idx,1)

6 个评论

? OP has mentioned "I want to call data in the matrix by using string which is defined by rand command."
corners = 'ABC'
I know....what is the necessity to call it by strings? At the end if strings are there..he has to use eval which is not advised. When there is a option of calling by indices why to use strings?
I need B and C definition. This answer is not useful for me. Because I am trying to shorten this long script to below script.
for i=1:1000
r = randi([1 3]);
switch r
case 1 %A
x(i+1)=(x(i)+A(1))/2;
y(i+1)=(y(i)+A(2))/2;
case 2 %B
x(i+1)=(x(i)+B(1))/2;
y(i+1)=(y(i)+B(2))/2;
case 3 %C
x(i+1)=(x(i)+C(1))/2;
y(i+1)=(y(i)+C(2))/2;
end
end
for i=1:10000
corners = 'ABC';
randompick = corners(randi(numel(corners)));
disp(randompick)
x(i+1)=(x(i)+randompick(1))/2;
y(i+1)=(y(i)+randompick(2))/2;
end
Did you notice that I have copied all the three vertices in a single matrix A...? Why do you think the code is not useful?
A = [A ; B ; C] ;
for i=1:1000
r = randi([1 3]);
x(i+1)=(x(i)+A(r,1))/2;
y(i+1)=(y(i)+A(r,2))/2;
end
No issues.....No aplogizes.......you are welcome.......

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