changing the string "JF 2009" to two seperate strings "J 2009" " F2009" (reposted)

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salva
salva 2012-7-26
Dear all I have the following cell matrix
A={
1 'SLO' ' '
1 'SLO' ' '
1 'SLO' 'JF 2009'
1 'SLO' 'MA 2009'
1 'SLO' 'MJ 2009'
1 'SLO' 'JA 2009'
1 'SLO' 'SO 2009'
1 'SLO' 'ND 2009'
1 'SLO' 'JF 2010'
1 'SLO' 'MA 2010'
1 'SLO' 'MJ 2010'
1 'SLO' 'JA 2010'
1 'SLO' 'SO 2010'
1 'SLO' 'ND 2010'
1 'SLO' 'JF 2011'
1 'SLO' 'MA 2011'
1 'SLO' 'MJ 2011'
1 'SLO' 'JA 2011'
2 'SLO' ' '
2 'SLO' ' '
2 'SLO' 'JF 2009'
2 'SLO' 'MA 2009'
2 'SLO' 'MJ 2009'
2 'SLO' 'JA 2009'
2 'SLO' 'SO 2009'
2 'SLO' 'ND 2009'
2 'SLO' 'JF 2010'
2 'SLO' 'MA 2010'
2 'SLO' 'MJ 2010'
2 'SLO' 'JA 2010'
2 'SLO' 'SO 2010'
2 'SLO' 'ND 2010'
2 'SLO' 'JF 2011'
2 'SLO' 'MA 2011'
2 'SLO' 'MJ 2011'
2 'SLO' 'JA 2011'
}
As you can see I have bimontly data. I want to modify the last column so as to have months like
Amodified={
1 'SLO' ' '
1 'SLO' ' '
1 'SLO' 'J 2009'
1 'SLO' 'F 2009'
1 'SLO' 'M 2009'
1 'SLO' 'A 2009'
1 'SLO' 'M 2009'
1 'SLO' 'J 2009'
1 'SLO' 'J 2010' }
and so forth
The previous answers were correct and I thank these guys. Yet their code can be applied for small number of individuals. In my case I have 30000 individuals.
Could you please help me?
thanks
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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-7-26
编辑：Andrei Bobrov 2012-7-26
Amodified = [];
for jj = 1:size(A,1)
if ~strcmp(A{jj,3},' ')
z = [A([jj,jj],1:2),...
[{[A{jj,3}(1),A{jj,3}(3:end)]};...
{[A{jj,3}(2),A{jj,3}(3:end)]}]];
else
z = A([jj],:);
end
Amodified = [Amodified;z];
end

更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-7-26
编辑：Azzi Abdelmalek 2012-7-26
%i tryed this code to test a 30000x3 array
for k=1:10;A=[A;A];end % A is now a 36864x3
n=size(A,1)
c1=num2cell([1:n]')
a=[c1 A]
b=sortrows(a,4)
B=b(:,4)
d=max(find(cellfun(@(x) length(x)>2,B)==0))
C=b(d+1:end,:)
n1=size(C,1)
ind1=1:2:2*n1-1;ind2=2:2:2*n1,C1=C;C2=C;
C1(:,4)=cellfun(@(x) strtrim(regexprep(x,x(1),'')),C(:,4),'UniformOutput',false)
C2(:,4)=cellfun(@(x) strtrim(regexprep(x,x(2),'')),C(:,4),'UniformOutput',false)
D=cell(n1*2,4); D(ind1,:)=C2; D(ind2,:)=C1;
E=sortrows([b(1:d,:) ; D],1);
Result=E(:,2:4)
% the program works % depending on the performance of your computer, it takes maby longer,

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