sort element in cell
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A={[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[4,5,6,11,12,13,14],[5,6,7,8],...
[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[6,31],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]};
ref=31;
base = cellfun(@(m)any(ismember(m,ref)),A,'uni',0);
base_mes=A{find([base{:}]==1)};
include_base = cellfun(@(m)any(ismember(m,base_mes)),A,'uni',0);
result=cell(1,numel(include_base));
index_other=find([include_base{:}]==1);
for i=1:size(index_other,2)
result{i}=A{index_other(i)};
end
base_mes=[6,31], I want to find 6 and 31 in A, after this sort A according to 31 and 6.
result={[6,31],[4,5,6,11,12,13,14],[5,6,7,8],[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]}
5 个评论
Stephen23
2019-2-20
编辑:Stephen23
2019-2-20
- "there are more cells that contain 31" -> "How should I fix it?" -> only you can decide how to "fix" that, or if it needs "fixing" at all. You can tell us what you want to happen, but we cannot tell you what you want to happen in that situation.
- "what if the cell(s) containing 31, contain more than 2 numbers" -> my answer does not assume anything about how many elements the vectors have.
采纳的回答
Stephen23
2019-2-20
编辑:Stephen23
2019-2-20
You can easily use logical indexing for this:
A = {[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[4,5,6,11,12,13,14],[5,6,7,8],[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[6,31],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]};
ref = 31
idr = cellfun(@(v)any(ismember(v,ref)),A);
vec = A{idr};
idv = cellfun(@(v)any(ismember(v,vec)),A);
Z = [A(idr),A(idv&~idr),A(~idv)];
Giving:
>> Z{:}
ans =
6 31
ans =
4 5 6 11 12 13 14
ans =
5 6 7 8
ans =
1 2 3 4 5 8 9 39
ans =
2 3 17 18 25 26 27
ans =
3 4 14 15 16 17 18
ans =
10 11 12 13
ans =
16 21 22 23 24
ans =
26 28 29
ans =
2 30
ans =
10 32
ans =
19 33
ans =
20 34
ans =
22 35
ans =
23 36
ans =
25 37
ans =
29 38
4 个评论
Stephen23
2019-2-21
>> fun = @(v) sort(0-ismember(v,vec)-(v==ref));
>> [~,ids] = cellfun(fun,Z,'uni',0);
>> Z1 = cellfun(@(v,x)v(x),Z,ids,'uni',0);
>> Z1{:}
ans =
31 6
ans =
6 4 5 11 12 13 14
ans =
6 5 7 8
ans =
1 2 3 4 5 8 9 39
ans =
2 3 17 18 25 26 27
ans =
3 4 14 15 16 17 18
ans =
10 11 12 13
ans =
16 21 22 23 24
ans =
26 28 29
ans =
2 30
ans =
10 32
ans =
19 33
ans =
20 34
ans =
22 35
ans =
23 36
ans =
25 37
ans =
29 38
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