Creating possible addition of a number
1 次查看(过去 30 天)
显示 更早的评论
I have a set of array A
A= [1 2 4 8 16]
For example I want a set of number that make up total of 4 (from A), it would be
B=[1 1 1 1] *total in array B would be 4*
B=[1 1 2]
B=[2 2]
B=[4]
Is it possible to do it in Matlab?
采纳的回答
John D'Errico
2019-2-24
编辑:John D'Errico
2019-2-24
Trivial, if you download my partitions function from the File Exchange.
A = [1 2 4 8 16];
partitions(4,A)
ans =
4 0 0 0 0
2 1 0 0 0
0 2 0 0 0
0 0 1 0 0
Each row of the result tells you how many times that element appears in the target sum.
Find it here:
Note that the number of such partitions can be immense for some problems. You can easily overwhelm such a tool. For example, I have another utiility that will count the number of partitions of an integer.
numberOfPartitions(1000)
ans =
24061467864032622473692149727991
Thus as the sum of numbers in the set [1:1000]. It gets big, and does so pretty fast.
0 个评论
更多回答(1 个)
Stephen23
2019-2-24
Download John D'Errico's excellent partitions:
and use it like this:
>> A = [1,2,4,8,16];
>> M = partitions(4,A);
>> F = @(v)repelem(A,v);
>> C = cellfun(F,num2cell(M,2),'uni',0);
>> C{:}
ans =
1 1 1 1
ans =
1 1 2
ans =
2 2
ans =
4
2 个评论
John D'Errico
2019-2-24
One of the things I should have added as an option, was the ability to return the partitions in an expanded form, something much like Stephen did here. You can never have too many options in an interface. Well, at least not until you do. ;-)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Multidimensional Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!