Size of Images varying
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Input = imread('baby1.jpeg') ;
size(Input)
P=rgb2gray(Input);
image= im2double(P);
[m n ] = size(A);
Med = [];
%Modified filter
for i=2:m-1
for j=2:n-1
Med(1) = image(i,j);
Med(2) =image(i-1,j) ;
Med(3) = image(i-1,j+1);
Med(4) = image(i,j-1);
Med(5) = image(i,j+1);
Med(6) = image(i+1, j-1);
Med(7) = image(i+1,j);
Med(8) = image(i+1,j+1);
Afilteres(i, j) = median(Med(:));
end
end
imshow(Af);
In this the size of image varies
size(P)=201 300
size(Af)
200 299
PLease help
2 个评论
Sean de Wolski
2012-7-30
In reponse to the flags and requests for deletion. I will not delete this question since Andrei, Wayne and IA all put effort into helping you.
采纳的回答
Andrei Bobrov
2012-7-28
编辑:Andrei Bobrov
2012-7-28
m = size(A);
A1 = zeros([m(1:2) + 2,m(3)]);
A1(2:end-1,2:end-1,:) = A;
Af = zeros(m);
for ii = 1:m(1)
for jj = 1:m(2)
k = reshape(A1(ii:ii+2,jj:jj+2,:),[],1,3);
Af(ii,jj,:) = median(k([1:4,6:9],:,:)); % EDIT
end
end
2 个评论
Image Analyst
2012-7-28
You forgot to exclude the middle pixel when taking the median, like he did. Though I don't know what the use of this strange type of median filter would be. Maybe he can explain that.
更多回答(2 个)
Wayne King
2012-7-28
The Image Processing Toolbox has medfilt2
3 个评论
Wayne King
2012-7-28
The file exchange appears to have median filter implementations, but I'm guessing if you're not allowed to use medfilt2, then you're not supposed to use those either
Image Analyst
2012-7-28
编辑:Image Analyst
2012-7-28
If the built-in function must not be used, then it must be some kind of homework assignment, which means that code solutions provided by Answers must not be used either. Too bad because I have a nice demo using blockproc that I could have given you. However it's strange that median(), the 1D version, can be used while medfilt2(), the sliding 2D version, cannot be used.
Image Analyst
2012-7-28
Of course the image sizes are different, because you're sliding a window along, and you have it so that when the edge of the window touches the edge of the image, it stops. So of course the output image will not be as big as the input image.
Again, I have demo code but since you said you're not allowed to use built in functions, and probably not code handed over to you in Answers or code you got from the File Exchange, I won't post it. Yeah, sometimes instructors/professors are picky about doing your own work.
4 个评论
Image Analyst
2012-7-30
编辑:Image Analyst
2012-7-30
Well then you're all set, because Andrei gave you code that used median() (and you've already accepted his answer), and I suggested using sort() and taking the middle element. So I'm assuming that you're done now.
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