Can I divide a linear array by a number which larger than its size ?

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Zara Khan 2019-3-16

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评论： Image Analyst 2019-3-17

I am having a cell array. Each element of the cell array is a linear array . These arrays are of different sizes. when diving each array to some equal parts then I am not getting consistent parts. Suppose I want to divide each cell array by 20. When the size is greater than 20 then its ok. but when less than 20 then I am not getting any consistent parts. I want to divide each linear array to 20 equal parts. whatever the size is I dont want any padding of values. If the array size is 1×17 and diving with 20 will give 20 equal parts . The partition size will be less than 1. How can I do this ?

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Zara Khan 2019-3-16

cell array.png

I am getting "cell array.png' cell array. Now I want to divide each cell equally to 20 partitions

Image Analyst 2019-3-16

Unless you want to do some interpolation/resizing, you can't because each array in each cell is not a multiple of 20.

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KSSV 2019-3-16

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You interpolate your data into your desired size and then reshape. Read about interp1.

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Zara Khan 2019-3-16

how can I handle an entire cell array with this ? Suppose my first cell contains an array of size 1×17, diving with 20 will give a size of 0.85. Is this possible to do here ? Next cell contains 1×31 , diving with 20 again, next cell is 1×131 again diving with 20. Cell array contains 16 colums and 1000 rows . How can I loop over this process? Please help.

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Walter Roberson 2019-3-16

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https://ww2.mathworks.cn/matlabcentral/answers/450389-can-i-divide-a-linear-array-by-a-number-which-larger-than-its-size#answer_365702

在 MATLAB Online 中打开

Next20 = @(V) ceil(length(V)/20) * 20;
Interp20 = @(V) interp1(V, linspace(1, length(V), Next20(V)));
Split20 = @(V) mat2cell(V, 1, 20*ones(1, length(V)/20));
new_cell = cellfun( @(V) Split20(Interp20(V)), cell_array, 'Uniform', 0);