transforming two date vectors

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Sabbas
Sabbas 2012-8-6
Dear all,
I have
A={
'2/11/2008'
'30/11/08'
'28/12/08'
'25/01/09'
'22/02/09'
'22/03/09'
'19/04/09'
'17/05/09'
'14/06/09'
'12/7/2009'
'9/8/2009'
'6/9/2009'
'4/10/2009'
'1/11/2009'
'29/11/09'
'27/12/09'
'31/01/10'
'28/02/10'
'28/03/10'
'25/04/10'
'23/05/10'
'20/06/10'
'18/07/10'
'15/08/10'
'12/9/2010'}
and
B={
'1/4/2009'
'2/1/2009'
'3/1/2009'
'4/5/2009'
'5/3/2009'
'5/31/2009'
'7/5/2009'
'8/2/2009'
'8/30/2009'
'10/4/2009'
'11/1/2009'
'11/29/2009'
'1/3/2010'
'1/31/2010'
'2/28/2010'
'4/4/2010'
'5/2/2010'
'5/30/2010'
'7/4/2010'
'8/1/2010'
'8/29/2010'
'10/3/2010'
'10/31/2010'
'11/28/2010'
'1/2/2011'
'1/30/2011'
'2/27/2011'
'4/3/2011'
'5/1/2011'
'5/29/2011'
'7/3/2011'
'7/31/2011'
'8/28/2011'
'10/2/2011'
'10/30/2011'
'11/27/2011'
'1/4/2009'
'2/1/2009'}
Sometimes I have either vector A or vector B. I want to find a unified code that will convert these vectors to the format dd/mm/yy irrespective of whether I have A or B
thanks
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显示 1更早的评论
Sabbas
Sabbas 2012-8-6
B has a characteristic. you get dates of the format '10/31/2010' So you can have mm/dd/yyyy whereas in the first vector you do not have such cases. I suppose you can use this to "know" when you have vector A or vector B
thanks
Matt Fig
Matt Fig 2012-8-7
So you can guarantee that every set of dates will have at least one day D where D>12? You did not specify that in the original statement, but it is good to know!

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-8-7
a = regexp(DateInput,'(^\d*)(?=/)','match');
if any(str2double(cat(1,a{:}))>12)
dfmt = 'dd/mm/yyyy';
else
dfmt = 'mm/dd/yyyy';
end

更多回答（1 个）

per isakson
per isakson 2012-8-6
编辑：per isakson 2012-8-6
Try
cac = cellfun( @(str) transpose( sscanf( str, '%d/%d/%*d' ) ) ...
, A, 'uni', false );
num = cell2mat( cac );
isd = any( num >= 13, 1 );
if all( not( isd ) )
msg = 'Cannot decide';
elseif all( isd )
msg = 'Illegal date';
elseif isd(1)
msg = 'day first';
elseif isd(2)
msg = 'month first';
else
msg = 'Error in code';
end
  1 个评论
per isakson
per isakson 2012-8-6
To avoid the long line I edited and introduced an error, which is now fixed.

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