x(i+1)=y(i)-((f(y(i))/d(y(i)))); // error in this line..

1 次查看（过去 30 天）

显示更早的评论

Umar Bhai 2019-4-4

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/454315-x-i-1-y-i-f-y-i-d-y-i-error-in-this-line

回答： KSSV 2019-4-4

在 MATLAB Online 中打开

% Program Code of Newton-Raphson Method in MATLAB 
 
a=input('Enter the function in the form of variable x:','s');
y(1)=input('Enter Initial Guess:');
error=input('Enter allowed Error:');
f=inline(a);
dif=diff(sym(a));
d=inline(dif);
for i=1:100
x(i+1)=y(i)-((f(y(i))/d(y(i))));x(i+1)=y(i)-((f(y(i))/d(y(i))));
error(i)=abs((y(i+1)-y(i))/y(i));
if err(i)<error
break
end
end
root=y(i);

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

KSSV 2019-4-4

You need to rethink on your code. There is no y(i+1) and you are extracting it. Google for Newton Raphson code and you will get. LEarn from it.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

KSSV 2019-4-4

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/454315-x-i-1-y-i-f-y-i-d-y-i-error-in-this-line#answer_369000

Refer here: https://in.mathworks.com/matlabcentral/fileexchange/68885-the-newton-raphson-method

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

类别

Mathematics and Optimization Optimization Toolbox Systems of Nonlinear Equations Newton-Raphson Method

在 Help Center 和 File Exchange 中查找有关 Newton-Raphson Method 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Translated by